Regents Review – Geometry – 2023
Regents Review – Geometry – 2023

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COMMON CORE ALGEBRA II HOMEWORK #1 – FUNCTIONS
The function f(x) = x^2x-3 is graphed on the grid below. Which of the following represents its domain and range written in interval notation?
Domain: [-2,4] Range: [4,6]
Domain: (-30,âˆž)
Range: [A,âˆž)
Domain: [-2,4] Range:
Domain: (-2,4) Range: (3,6)
y = f(x)
Which of the following values of x would not be in the domain of the function y = âˆš(x+4)? X = T = 3
T = -8
T = x – 2 f(x) =
Which of the following values of x would not be in the domain of the function defined by x+3? (1) x = -3 1-3
r = 2
1 = -2
Which of the following would represent the domain of the function y = âˆš(6-2x)? (1) {x:x>3} {x:x<3} (2) {x:x<3} {1:2,3} The function y = f(x) is completely defined by the graph shown below. (a) Evaluate f(-4)
Evaluate f(3)
State the domain and range of this function using interval notation
Domain:
Range:
f(x) = x^5 and g Page, find value 2^2 for each of the following:
6. Given OctdatOnnt Cnd TTT IOOTIOAC CCdrtenoeTe Cnr
TedOnt

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02:37

Question 3: Consider the function f(x).(a) Is the point (2, 3) on the graph of f? (b) If so, what is f(2)? What point is on the graph of f? (c) If f(1) = 1, what is f(1)? What point(s) are on the graph of f? (d) What is the domain of f? List the x-intercepts, if any, of the graph of f. List the y-intercept, if there is one, of the graph of f.

Question 4: Figure 15Let f be the function whose graph is shown in Figure 15. The graph of f might represent the distance that the bob of a pendulum is from its equilibrium position at time t. Negative values only mean that the bob is to the left of its equilibrium position, and positive values mean that the pendulum is to the right of its equilibrium position.

What are f(0), f(1), and f(2)? What is the domain of f? What is the range of f? List the x-intercepts (recall that these are the points where the graph crosses or touches the x-axis). How many times does the line y = 0 intersect the graph? For what values of x does f(x) = 0? For wha…

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Match the following:1. the range set of E = {(3, 3), (4,4), (5,5), (6, 6)}(3, 4, 5, 6)2. the range and domain of F = {(x, y) | x + y = 10}domain = {all real numbers}, range = {y = 3}3. the range and domain of P = {(x, y) | y = 3}4. the domain set of C = {(2,5), (2, 6), (2, 7)}(2)

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Assignment Relations and Functions: Definitions Attempt 1 of 2

SECTION 2 of 2

Match the following:the range set of E = [(3, 3), (4, 4), (5, 5), (6, 6)]{3, 4, 5, 6}the range and domain of F = {(x, y) | x + y = 10}domain = {all real numbers}, range = {y = 3}the range and domain of P = {(x, y) | y = 3}the domain set of C = {(2, 5), (2, 6), (2, 7)}domain range = {all real numbers}

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I(x) = 4x^2 – x – 3

a) Does substituting x = % into the given equation result in 15?b) Does substituting x = into the given equation result in -2?c) What is the point ( -2, 15) on the graph of f?d) What is f(x)?e) What point is on the graph of f?f) What is the domain of f?g) List the x-intercepts, if any, of the graph of f.h) List the y-intercept, if any, of the graph of f.i) If x = , what point(s) are on the graph of f?j) If f(x) = 3, what is x?k) Using the information from the previous step, list the point(s) on the graph of f where f(x) = .l) What is the domain of f?m) List the x-intercepts, if any, of the graph of f.n) List the y-intercept, if any, of the graph of f.

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Math 140 Final Exam All Sections including SL Catter Dcanba 10-14, 2012 What is the domain of the function defined by the equation v = h(z+ 2y^2 (0) (-x,-2) (6) (-x,2) (c) (-2,0) (d) (20) (e) (0,-) (5) (-0,01)

If b and n are the numbers 0 such that the polynomial 2 + br + bas + 2i is a zero, find b+c(0) 3(6) 4(c) 5(d) 6

Let R(r) = 3r^2+3+2+2. Then R(z) has 4n oblique asymptote &: 2+âˆš2 (4) v=3-4 (5) v=3-3 (c) y=3-2 (d) v =31 – 1 (e) y=3 46

Solve the inequality: 3t^2 < 0 (a) (-0,-1) U (0,2) (6) (-1,0) U (0) (d) (-1,0) U {2} (-1,0] (1) (-1,0) (g) All real numbers

Solve the inequality: t > 1 (2) (-1,1) (6) (-1,7) (c) [-1,1) (d) (-0,1) U (lx) (e) (-âˆž,-1) U (1,âˆž)

Find the remainder when 30 + 2P – 0r – 2 is divided by < – 1 (d) 1 (c) 2 (0) (J=3 () -2 (c) -1

Polynomial p(r) = 22r^3 – 4r^2 + 6r – 7 are pucitte? How many zeros of the (c) 2 (d) 3 (e) 4 (e) 0 (6) 1

Transcript

All kay, so your domain is your x values and, as you can see that here, as you go up your domain, your values are slowly extending outward, so your domain is negative infinity to infinity. Because of that, i can stop at the rest of them, because none of the other ones have a domain from negative infinity to infinity. But the range is your a value. My y values start right here at 1234 point, so they start at negative 4 and they go to infinity and it’s a bracket because it’s actually equal to it. So that’s why that’s the range okay, so the next 1 would what would not be in the domain. So which 1 of these would make square root x, plus 4, less than 0? So if i plug in 0, so 0 plus 4 is 4 and i can do the square root of 4, so that span so 0 is right. 5 plus 4 gives me a square root 9. That works negative 3, so negative, 3 plus 4 gives me a positive 1 square root of 1. That 1 works is 1 all right now. Negative 8 negative 8 plus 4 gives me the square root of negative 4, which is imaginary, and that is not part of my graph, so this would make would not be in the domain which of the following would not be part of the domain. So we need to know which 1 for your denominator x, plus 3, cannot equal 0, so x cannot be equal to negative 3. So negative 3 is your excluded value all right so from here to find the domain. I’M gonna set that denominator equal…