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2) Evaluate the integral:

(2x – 2)e^(x^2-2x)dx

Evaluate the integral: 3) -3+x dx / (2 – 6x + x^2)

Evaluate the integral by separating the fraction and using 4) x – âˆš(Nxt^4) dx / (xâˆš(Nx+4))

5) Evaluate the integral:

2x^2 + x + 6 dx / (x – 2)

Hint: Divide first to find the quotient and the remainder.

Evaluate the integral:

6)

âˆ«3x sin(2x) dx

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$ \displaystyle \int \frac{dx}{x^2 – 2x} $

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$ \displaystyle \int_2^3 \frac{x (3 – 5x)}{(3x – 1)(x – 1)^2}\ dx $

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Transcript

here. We want to take the integral given. Well this is gonna be a nice use substitution because if I say U equals X squared minus two X. Its derivative directly shows up because D. U. Is gonna be two x minus two. And that’s this. But let’s remember the D ax. So I’m gonna be replacing two x -2 d. x. With D. U. So the other thing I need to figure out is the limits. If I have X equals zero, what is you? Well that means I just need to find U. Of zero which is zero squared minus two times zero which is zero. And then let’s find you a three which is three…

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