Derivative of cos(x^2), cos^2(x), and cos(2x) with Chain Rule | Calculus 1 Exercises
Derivative of cos(x^2), cos^2(x), and cos(2x) with Chain Rule | Calculus 1 Exercises

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1-16 Differentiate. f(x) = 3√(2cosx) + 3f(x)sinx – 2cotx
g(t) = tcos^2(t)
h(0) = csc(0) + e^cot(0)
y = e^(-cosu + cu)
y = sin(0)cos(0)tanx
y = sec^2(0)cosx
f(0) = 1 + sec(0)
y = 1 – sinx
y = 1 – secx
y = tanx
y = 1 + t
y = x^e^(sinx)tanx
f(x) = x^e^(CSCx)

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In Exercises $33-54,$ find the derivative of the function.$$y=e^{x}(\sin x+\cos x)$$

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In Exercises $23-36,$ find the derivative.$$y=\cos ^{-1}\left(x+\sin ^{-1} x\right)$$

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In Exercises $39-54$ , find the derivative of the trigonometric function.$$y=\frac{3(1-\sin x)}{2 \cos x}$$

Transcript

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You are watching: 2cotx g(t) = tcos^2(t) h(0) = csc(0) + e^cot(0) y = e^(-cosu + cu) y = sin(0)cos(0)tanx y = sec^2(0)cosx f(0) = 1 + sec(0) y = 1. Info created by Bút Chì Xanh selection and synthesis along with other related topics.