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KINEMATICS
KINEMATICS
KINEMATICS
GRAVIATION
LAWS OF MOTION
A body slides down a smooth inclind placne when released form the tip, whille another body fall freely the same point . Which on will strike the ground earlier ?
A stone drope from the window of a stationary bus takes 4 seconds to reach the ground. In what time the stone will reach the groun when the bus is moving with (a) constant velocity of 108 km h^(-1)(b)constantae≤rationof 2 km h&(-2).
The direction in which an obect moves is given by thedirection of velocity of the object and bot by the direction of acceleration. Explain this staement with suitable exmple.
Assertion: For the plantes orbiting around the sun, angular speed, linear speed, K.E. changes with time, but angular momentum remains constant.
Reason: No torque is acting on the rotating planet. So its angular momentum is constant.
Assertion : A person receive more injury when he falls from a height on a concrete pavement than when he falls from the same hight on a bed of sand
Reason : The force exerted on the person by the concrete pavement is more than that exerted by the bed of sand .
Let ABCD is a parallelogram and →AC,→BD be its diagonal, then →AC+→BD is
A parallelogram ABCD. Prove that −−→AC+−−→BD=2−−→BC’
ABCD is a parallelogram with AC and BD as diagonals. Then, A→C−B→D=
If ABCD is a parallelogram, then −−→AC−−−→BD=
ABCD एक चतुर्भुज है और AC और BD इसके विकर्ण हैं । सिद्ध करो कि सदिश −−→AB+−−→DC=−−→AC+−−→DB
ABCD एक समांतर चतुर्भुज है ।AC और BD इसके विकर्ण है । सिद्ध कीजिए –
−−→AC+−−→BD=2−−→BC
−−→AC−−−→BD=2−−→AB.
ABCD एक समान्तर चतुर्भुज हैं और AC, BD इसके विकर्ण हैं|
(a) −−→AB को −−→AC और −−→BD के रूप में व्यक्त करें| (b) −−→AC को −−→BD के रूप में व्यक्त करें|
साथ ही यह सिद्ध करें कि −−→AC+−−→BD=2−−→BC,−−→AC−−−→BD=2−−→AB
ABCD एक समांतर चतुर्भुज है | AC और BD उसके विकर्ण है सिद्ध कीजिए –
−−→AC−−−→BD=2−−→AB
¯¯¯¯¯¯AC and ¯¯¯¯¯¯BD are the diagonals of the parallelogram ABCD. Prove that,
−−→AC+−−→BD=2−−→BC and −−→AC−−−→BD=2−−→AB
ABCD সামান্তরিকের ¯¯¯¯¯¯AC ও ¯¯¯¯¯¯BD হল কর্ণ | প্রমাণ করো যে, −−→AC+−−→BD=2−−→BC এবং −−→AC−−−→BD=2−−→AB |
