The properties of a parallelogram are listed below. We will use a parallelogram ABCD to show these properties.
Property #1
Opposite sides of a parallelogram are congruent.
The length of AB is equal to the length of DC.
The length of BC is equal to the length of AD.
Here is how to prove that opposite sides of a parallelogram are congruent.
Property #2
Opposite angles of a parallelogram are congruent.
Angle A is equal to angle C
Angle B is equal to angle D
Given parallelogram ABCD, we need to prove ∠A ≅ ∠C; ∠B ≅ ∠D
1. Given
ABCD is a parallelogram
2. Consecutive angles are supplementary angles in a parallelogram (property #4)
∠A + ∠B = 180 degrees
∠B + ∠C = 180 degrees
3. Transitive property in properties of equality
∠A + ∠B = ∠B + ∠C
4. Subtraction property in properties of equality
∠A + ∠B – ∠B = ∠B – ∠B + ∠C
5. ∠A = ∠C
Using similar reasoning, you can show that ∠B ≅ ∠D
Property #3
The diagonals of a parallelogram bisect each other.
Diagonal AC (red line) intersects and bisects diagonal BD (green line) at E.
Given parallelogram ABCD, we need to prove that segment AC and segment BD bisect each other at E.
1. Given
ABCD is a parallelogram
2. Definition of parallelogram
Segment AB || segment DC
3. Parallel lines cut by a transversal form congruent alternate interior angles
∠1 ≅ ∠4; ∠2 ≅ ∠3
4. Opposite sides of a parallelogram are congruent
Segment AB ≅ segment DC
5. Triangle ABE is congruent to triangle CDE by ASA (angle-side-angle)
6. Segment AE ≅ segment CE and segment BE ≅ segment DE by CPCTC (corresponding parts of congruent triangles are congruent)
7. Definition of bisector
Segment AC and segment BD bisect each other at E.
Property #4
Consecutive angles are supplementary or add up to 180 degrees.
Angle A + angle B = 180 degrees
Angle B + angle C = 180 degrees
Angle C + angle D = 180 degrees
Angle D + angle A = 180 degrees
Property #5
Each diagonal of a parallelogram turns the parallelogram into 2 congruent triangles.
Triangle ABC is congruent or identical to triangle ADC.
Triangle BCD is congruent or identical to triangle BAD.
Example #1: Use the parallelogram below to find the length of segment BC and segment AD.
Since the opposite sides of a parallelogram are congruent, the length of segment BC is equal to the length of segment AD.
4x – 10 = 3x + 5.
Subtract 3x from each side
4x – 3x – 10 = 3x – 3x + 5
Simplify each side
x – 10 = 5
Add 10 to both sides of the equation.
x – 10 + 10 = 5 + 10
Simplify
x = 15
BC = AD = 4x – 10 = 4 times 15 – 10 = 60 – 10 = 50
Example #2: Use the parallelogram below to find the length of segment AC and segment BD.
Since the diagonals of a parallelogram bisect each other, we get the following results:
This leads to a system of linear equations to solve
2y – 4 = 4x
y = x + 4
Substitute x + 4 for y in 2y – 4 = 4x
2(x + 4) – 4 = 4x
Distribute
2x + 8 – 4 = 4x
Simplify
2x + 4 = 4x
Subtract 2x from each side
2x – 2x + 4 = 4x – 2x
Simplify
4 = 2x
x = 4/2 = 2
y = x + 4 = 2 + 4 = 6
AC = AI + CI = 2y – 4 + 4x = 2×6 – 4 + 4×2 = 12 – 4 + 8 = 16
BD = BI + DI = x + 4 + y = 2 + 4 + 6 = 12
Check also the lesson about parallelogram to learn some interesting stuff about the parallelogram such as:
Jun 09, 23 12:04 PM
Jun 06, 23 07:32 AM
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