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Find the derivative
dy dx
tan-1 x2 y = x2 + 1

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02:53

Find $dy/dx$ by implicit differentiation.$tan (x – y) = \frac {y}{1 + x^2}$

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06:17

find dy/dx

02:37

y.sec^2(x)dx+(tan(x)+y)dy =0, y(0)=1

Transcript

Hello students, the given function y is equal to tan inverse of x square by x square plus 1. Now, we differentiate y, differentiating y with respect to x, we have dy by dx is equal to x square plus 1 into d dx of tan inverse x square minus tan inverse x square into d dx of x square plus 1 divided by x square plus 1 whole square. So, this is equal to x square plus 1 into 2 x by x to the power 4 plus 1 minus tan inverse x square into 2 x divided by x square plus 1 whole square. Now, simplifying this, we have 1 by x square plus 1 whole square root 2…