[8/8/2023] MARKET ĐI CHẬM, KHÔNG CÓ LÃI. DAN STEEL LÀM GÌ?
[8/8/2023] MARKET ĐI CHẬM, KHÔNG CÓ LÃI. DAN STEEL LÀM GÌ?

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1. For the integral from 4 to 4 point 5 of 3 divided by square
root of quantity negative 15 plus 8 x minus x squared end quantity
times dx Part A: Determine if long division will be used for this
the integrand and use a u substitution to rewrite the integral with
new limits of integration. (15 points) Part C: Evaluate the
integral. Round to the nearest thousandth. (10 points)

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01:17

Evaluate the integrals in Problems $25-40 .$$\int_{1}^{4} 3 \sqrt{x} d x$$ 01:53 Use integration by parts to evaluate each integral.$$\int x^{5} \sqrt{x^{3}+4} d x$$ 02:10 Determine these indefinite integrals.$$\int\left(x^{4}+\frac{1}{8 \sqrt{x}}-\frac{4}{5} x^{-2 / 5}\right) d x$$ 05:15 Finding an Indefinite Integral In Exercises$15-46,\$ find the indefinite integral.$$\int \frac{1}{(x-1) \sqrt{4 x^{2}-8 x+3}} d x$$

Transcript

for this problem we are to evaluate the definite integral from 4 to 4.5 of three over the square root of negative 15 plus eight x minus x squared dx. Now, for the first part we want to determine if long division is necessary in order to simplify the integral. Now, since the integration is not a rational expression, then the long division is not necessary. And now for part B we have to simplify the inter grand. To simplify, we have to apply completing the square to the inside of the squared in the denominator. Now negative 15 plus eight X minus x squared is equal to negative of x squared -8 X -15. That’s negative of x squared minus eight X plus 16 plus one Which becomes 1- the square of X -4. So we can rewrite the integral and…