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Examine rectangle JKLM; shown below.

If JN = 1 + 3 and JL = 31,

determine the length of JL.

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01:40

The sides of a rectangle are in a ratio $3: 5,$ and the rectangle’s area is 135 sq $\mathrm{m}$. Find the dimensions of the rectangle.

00:34

a. Find the perimeter of the rectangle shown below.b. Find the area of the rectangle shown below.

00:22

Use the diagram of the rectangle.What is the perimeter of the rectangle when x 3?

03:01

a. Find the perimeter of the rectangle shown below.b. Find the area of the rectangle.(FIGURE NOT COPY)

Transcript

this question, this is given rectangle. J. K. L. M. Okay well J N. Is equal to X plus three and J. L. Is equal to three X plus one. And we have to find the value of jail. Okay now as this is a rectangle and we know that in a rectangle the diagnosed bisect each other. Okay so we can say this length that is jane will be called the nl because uh diagnose of a rectangle by stating that. Okay but I think with each other so in this case we can take care of the diagonal. Came will buy six. The diagram jail that is J. And equal to N. N. L. So as J. N. Is he called? Nl Okay this is one thing and another thing is jail. What is jail, jail is nothing but J. N. Plus J. N plus N. L. As jay and a golden L. We can write J. L. S. J. N Plus jane. Okay because what is J. So we can write as jane? So N. L. S. J. N. So that is J. L. is…

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