Calculus 1. Finding Equation of Secant Line.
Calculus 1. Finding Equation of Secant Line.

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Find an equation of the secant line containing (1, f(1)) and (2,f(2)).

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01:42

If $f(x)=x^{2}-4 x-3,$ find an equation of the secant line containing the points $(3, f(3))$ and $(5, f(5))$.

01:13

Find the slope of the secant line joining (2,f(2) and (3, f(3) for f(x) = -3x^2-8

01:08

Find an equation of the line $l$ tangent to the graph of $f$ at the given point. $f(x)=1 /(x+1)^{2} ;(0,1)$

01:59

In the above graph of y = f( x ), find the slope of the secant line through the points 3,f( -3 ) ) and ( 2, f( 2 ) ).

Transcript

In this problem, we have given a function: f x, equals 4 y x plus 3 x, 4 y x plus 3, and we have to find here the equation of second line. The equation second line second line joining containing the .1 comma, f, 1 and 2 comma f; 2. The equation of second line containing the .1 f, 1 and 2 f 2. Before finding the equation of second line. First, we’ll find the slope of the slope of second line. Let m is the slope so equal, f, 2 minus f, oneby, 2 minus 1, putting the values of f 2 and f 1. We have 4 y 2 plus 3 minus 4 y 1, plus 3, divided by 2. Minus 1 is 1. So m is equal 4 by 5 minus 4 by 4 point that is 1 by 1. It will be minus 1 by 5. So this is the slope of the second line. Now we have a point. Let’S say point…

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