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Find the derivative of y with respect to X for y = ( sin 3x)tan 3x.
Choose the correct derivative of y with respect to x for y = ( sin 3x)’ tan 3x
In sin 3X + cos 23x OA -3( sin 3x)tan 3x cos 23x In sin 3x + cos 3( sin 3x)tan 3x 23t/ 0B. sin 23X
In sin 3x coS 0 C. -3( sin 3x)tan 3x sin 23x In sin 3x + cos 23X 0 D: 3( sin 3x)tan 3x cos 23X

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03:42

Find the derivative of y with respect to x for y = (cos 3x)cot 3x. Choose the correct derivative of y with respect to x for y = (cos 3x)cot 3x.

cot 3x = cos 3x + sin 2(3x) * 3(cos 3x)^9 sin 3x

3(cos 3x)cot 3x = cos 3x * sin 2(3x) * cos 3x – sin 2(3x) * cos^2(3x) * 3(sin 3x)

02:17

‘Find the derivative of the function.Y = sin(tan 3x)y =’

02:07

Find the derivative of the trigonometric function.$y=\frac{3(1-\sin x)}{2 \cos x}$

03:22

Find the second derivative of the function.$$y=3 \cos x-x \sin x$$

Transcript

So here in this question, we have to find out a differential that is y equals to sine of 3 x and tangent of 3 of x. So from here we can see that the 2 of 3 x 3 of 2 of x, so from here we can see that d divided by the dx of y is equal to d, divided by the dx of sine raised to the power 23 x and tangent. To the power 2 f x, so this will become equal to d sine raised to the power square 3 of excusing the gen rule of differentiation d divided by x, tangent cube of 2 of x, plus tangent co, 2 of x d, divided by the dx of Sine square of 3 of x, so simplifying this, this will be equals to sine…