How To Calculate Oxidation Numbers – Basic Introduction
How To Calculate Oxidation Numbers – Basic Introduction

Okay, so when we assign oxidation numbers, there are a few rules that we need to follow. So group one Has a charge of plus one. Group two has a charge of plus two Hydrogen, since it’s in group one is typically plus one Flooring is typically -1, So is chlorine, it’s -1 And oxygen is typically -2. Okay, so we’re gonna keep these rules in mind while we go through this. So again rule, oxygen is always -2 unless it’s in peroxide, Which is not in any of the cases. So I’m going to go ahead and write -2 where all the oxygen are, so I don’t have to think about it later. So again, I’m writing, -2 all the oxygen, so I don’t have to think about it later. Okay. Mhm. Any other rules? So group one is always plus one and group two medals are always plus two. So sodium is a group one medal. So it’s going to be plus one 30 and will be plus one. So no sodium will be plus one 30 and it’s still plus one sodium is still plus one, sodium is still plus one and the sodium is plus one as well, hydrogen Is typically plus one so this is going to be plus one in this case, in the cases where it contains a metal It’s going to be -1. However, when it’s with the Polio, Ptarmigan, it’s going to be plus one. Okay, so that’s all my hydrogen all my sodium last, but not least. We have then chlorine and flooring R -1. So chlorine, it’s -1. Chlorine is -1. Okay, so then we know that the rest of the rules are that we have to make it equal to the overall charge. The overall charge for all of these is zero. Therefore we know that the charge of them has to equal zero. So for example carbon and A has to be whatever negative too, going to be x minus two equals zero. So that means carbon has to be plus two. And let her be though oxygen is -2, there’s two of them. So overall this is a negative for charge. We need it to be neutral. Therefore this carbon is going to be positive for So it depends on what it is with let her see we have two that are plus one. So we have plus two, We also have three that are -2. So we have -6. So to make that neutral overall carbon is going to be plus four. His plus four times plus 12 plus four plus two plus six And 2 -3 is -6. So that gives us a charge overall of zero for letter D. We have two that are plus one, So that’s going to be plus two. So we have plus two And -2 times four is negative…

You are watching: SOLVED: Indicate the oxidation number of carbon and sulfur the in following compounds. Procedure a. CO b. CO2 c. Na2CO3 d. Na2C2O4 e. CH4 f. H2CO g. SO2 h. SO3 i. Na2SO4 j. Na2SO3 k. Na2S2O3 l. Na2S4O. Info created by Bút Chì Xanh selection and synthesis along with other related topics.