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Use a change of variables or the table to evaluate the following indefinite integral.

sin X-8 sin x- sinx) cosx dx

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sin x-8 sin x- sinx) cosx dx

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01:29

Use a change of variables to evaluate the following integrals.$$\int \sin x \sec ^{8} x d x$$

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Evaluate the indefinite integral.

$ \displaystyle \int \sin x \sin(\cos x) \, dx $

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Use a table of integrals to evaluate the following indefinite integrals. Some of the integrals require preliminary work, such as completing the square or changing variables, before they can be found in a table.$$\int \frac{\cos x}{\sin ^{2} x+2 \sin x} d x$$

Transcript

in this problem we have to evaluate the given integral integral is here nine. Power 6 x minus eight. Fine Power four x minus Sine X. Into course X E X. To solve this. We will substitute here. Or we will change very well substitute U equal Sine X. Do you buy D axis levi dx hynix That is equal to D you by dx equal cause X. Today you equal because X D X putting this we will have the given integral in the form of £9.06. Sixes you power six -8. You par four minus you. And cause X dx is D. U. This can be integrated as two Parts 6 d. You and minus eight. You par five. Buch and minus you Do you bless it is the integrated constant of integration. So here we will use you power and the U. Is equal que parte en plus one by n plus one plus C. This is the formula of integral lock type this this is you…

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