How to find the percent composition of Fe(NO3)2 (Iron (II) Nitrate)
How to find the percent composition of Fe(NO3)2 (Iron (II) Nitrate)

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When the following molecular equation is balanced using the smallest possible integer coefficients the values of these coefficients are:
iron(II) chloride (aq)
silver nitrate (aq)
iron(II) nitrate (aq)
silver chloride (s)

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Transcript

according to the question, we have to tell the value of coefficients which have put in front of them according to the question, We have to tell the coefficients which are used to balance this chemical equation. First of all we will write their molecular formula for iron to chloride, it would be official too, And for silver nitrate it would be AGN. No three. Now they react to give aydin to nitrate and it has a formula of a fee and no 32. While silver chloride have a formula of a G C. L. So this is the reaction. And before balancing this equation, let’s try down the element present in this reaction. So element present our f that is iron, chlorine, cl ag, silver and nitrate. So we are using the full nitrate irrespective that it is made up of nitrogen and oxygen. We are using nitrate now on left hand side and right hand side on left hand side. Iron present is one while iron on right hand side is also one chlorine. On left hand side are two and chlorine on right hand side is one. Silver on left hand side is one and silver on right hand…

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You are watching: SOLVED: When the following molecular equation is balanced using the smallest possible integer coefficients the values of these coefficients are: iron(II) chloride (aq) silver nitrate (aq) iron(II) nit. Info created by Bút Chì Xanh selection and synthesis along with other related topics.