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What is the oxidation number of manganese in KMnO4?
6) consider the following equation: CrO4 SO;2 CrO4?
SOA
A) Write the oxidation numbers for each element underneath the above reaction B) Which species is oxidized? C) Which species is reduced? D) Which species is the oxidizing agent?
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02:03
What is the oxidation state of manganese in each of the following substances?a. $\mathrm{MnCl}_{2}$b. $\mathrm{KMnO}_{4}$c. $\mathrm{MnO}_{2}$d. $\operatorname{Mn}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{3}$
02:27
What is the oxidation state of manganese in each of the following substances?$$\begin{array}{ll}{\text { a. } \mathrm{MnCl}_{2}} & {\text { c. } \mathrm{MnO}_{2}} \\ {\text { b. } \mathrm{KMnO}_{4}} & {\text { d. } \mathrm{Mn}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{3}}\end{array}$$
00:50
Give the oxidation number of manganese in the following:(a) $\mathrm{MnO}_{4}^{2-} \quad$ (b) $\mathrm{Mn}_{2} \mathrm{O}_{3} \quad$ (c) $\mathrm{KMnO}_{4}$
02:16
What is the oxidation number of $\mathrm{Mn}$ in each of these species?(a) $\left(\mathrm{MnF}_{6}\right)^{3-}$(b) $\mathrm{Mn}_{2} \mathrm{O}_{-}$(c) $\mathrm{MnO}_{4}^{-}$(d) $\mathrm{Mn}(\mathrm{CN})_{6}^{-}$(e) $\mathrm{MnO}_{2}$
03:49
Determine the oxidation number of $\mathrm{Mn}$ in each of thes species.(a) $\left(\mathrm{MnF}_{6}\right)^{3-}$(b) $\mathrm{Mn}_{2} \mathrm{O}_{7}$(c) $\mathrm{MnO}_{4}^{-}$(d) $\mathrm{Mn}(\mathrm{CN})_{6}^{-}$(e) $\mathrm{MnO}_{2}$
Transcript
Hi everyone. So in problem five, what is the oxidation number of manganese in potassium permanganate? So oxidation number is the charge assigned of an element according to some set of rules and that will are known as the oxidation number rules. So suppose the oxidation number of manganese in potassium permanganate, statistical two X oxidation number of potassium that is plus one because the production belongs to group one element in the product table. So it’s oxidation number is plus one and the oxidation number of oxygen in oxide form existing minus two. And this summer of oxidation number of all the elements that is equal to zero. So that when one plus X plus four into minus two, that is equal to zero, so one plus X minus eight, that is equal to zero. So X -7 Is equal to zero. So the value of X that is equal to plus seven. So that means oxidation number of manganese That is equal to plus seven. We can also check in this way. So we have a petition par magnet. So oxidation number of production is plus one. Oxidation number of oxygen is minus two and manganese is plus seven. So that we have one plus seven plus four into minus two. So that 18 minus said that is a zero, there is no charge present on this compound. So therefore the correct answer is Plus seven. So oxidation Number of Manganese that is equal to Plus seven. Then in next problem problem # six. So in this problem we have to identify which one is oxidized…
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