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Published byHoratio Houston Modified over 7 years ago

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The Distributive Property Standard: Use the distributive property to express a sum of two whole numbers 1–100 with a common factor as a multiple of a sum of two whole numbers with no common factor. I Can Goal: I can apply the Distributive Property to rewrite addition problems by factoring out the Greatest Common Factor.

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Distributive Property A paperboy delivers or distributes newspapers to everyone who signs up to receive them. + OR ( + )

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Distributive Property We can use the same idea with numbers. 20+24 Steps to Solve: 1.Find the factors of each number. Factors of 20: 1, 2, 4, 5, 10, 20 Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

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Distributive Property We can use the same idea with numbers. 20+24 Steps to Solve: 2. Find the GCF. Factors of 20: 1, 2, 4, 5, 10, 20 Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

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Distributive Property We can use the same idea with numbers. 20+24 = 4(5 +6) Steps to Solve: 3. Pull out the GCF. Factors of 20: 1, 2, 4, 5, 10, 20 Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

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Distributive Property BUT, do they give the same answer? 20 + 24 OR 4(5 +6) =4420+24 =44 YES!

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Distributive Property We can also model the expression. 4(5 +6) 4 5 + 6 11

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Distributive Property Let’s Practice 12 + 20 Factors of 12: 1, 2, 3, 4, 6, 12 Factors of 20: 1, 2, 4, 5, 10, 20 GCF (12,20) = 4 12 + 20 = ___(__) + ___ (__) = ___ (____ + ____) 4 3 4 5 4 3 5

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1. 4 35

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